If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-0.8=-0.12x
We move all terms to the left:
x^2-0.8-(-0.12x)=0
We get rid of parentheses
x^2+0.12x-0.8=0
a = 1; b = 0.12; c = -0.8;
Δ = b2-4ac
Δ = 0.122-4·1·(-0.8)
Δ = 3.2144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.12)-\sqrt{3.2144}}{2*1}=\frac{-0.12-\sqrt{3.2144}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.12)+\sqrt{3.2144}}{2*1}=\frac{-0.12+\sqrt{3.2144}}{2} $
| -35-1x+6x^2=0 | | -35+-1x+6x2=0 | | 6+8x=21 | | 5(2x)−3=20x+15 | | 2+72x+324x^2=0 | | (5x÷8)-6=9 | | 64(0.5)^x=4 | | -4y-5=-4y-8 | | 324x^2+72x+2=0 | | 3-3/8a=4 | | 3a^2+7a-66=0 | | 9=a/6+8 | | 7v-v=30 | | 10x^2+7x+15=0 | | 88-v=218 | | 3-w/3=-7 | | 3+9x=6+2x | | 5-l=8 | | 3=9x=6=2x | | S^3-16s^2-9s+144=0 | | 4x=28÷4 | | 5x-4(6)=-20 | | 6(m–3)+4=286(m–3)+4=28 | | 10x+404=360 | | (4*x)^4/(2.1-3*x)^3/(1.4-2*x)^2=2.53 | | 4x+188=180 | | 3x+41=8x+6 | | 11.4+(0.5y)=9.9+(0.6y) | | 12-3×+4x=-2.5 | | N(x)=0.4x^2+9.6x+11 | | -5y+1.5=-20 | | 253=68-y |